Question

Log8=0.9031 and log9=0.9542 find 2log6

Answer 1

$given \: \: log(8) = 0.9031 \\ log( {2}^{3} ) = 0.9031 \\ 3 log(2) = 0.9031 \\ log(2) = \frac{0.9031}{3} = 0.3010$
$given \: \: log(9) = 0.9542 \\ log( {3}^{2} ) = 0.9542 \\ 2 log(3) = 0.9542 \\ log(3) = \frac{0.9542}{2} = 0.4771$
$2 log(6) = 2 log(2 \times 3) \\ = 2 \times ( log(2) + log(3) ) \\ = 2 \times (0.3010 + 0.4771) \\ = 1.5562$