log8 base 2 + log4 base 8
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Let log8(base2)=x i.e2^x=8=>2^x=2^3=>x=3
log8(base4)=y=>4^y=8=>2^2y=2^3
=>2y=3=>y=3/2
log8(base16)=z=>16^z=8=>2^4z=2^3
=>4z=3=>z=3/4
x+y+z=3+3/2+3/4=21/4.
log8(base4)=y=>4^y=8=>2^2y=2^3
=>2y=3=>y=3/2
log8(base16)=z=>16^z=8=>2^4z=2^3
=>4z=3=>z=3/4
x+y+z=3+3/2+3/4=21/4.
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