log8/log2*log3/log√3= 2 log x , find x
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Step-by-step explanation:
log(8)
*\frac{log(3)}{log( \sqrt{3})}
log(
3
)
log(3)
= 2*log(x)
3*\frac{log(2)}{log(2)}
log(2)
log(2)
*2*\frac{log( \sqrt{3}) }{log( \sqrt{3}) }
log(
3
)
log(
3
)
= 2*log(x)
3 = log(x)
x = anti log(3)
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