Math, asked by lbiswas268, 8 months ago


log8/log2*log3/log√3= 2 log x , find x

Answers

Answered by hxofkfyohdlkv
1

Step-by-step explanation:

log(8)

*\frac{log(3)}{log( \sqrt{3})}

log(

3

)

log(3)

= 2*log(x)

3*\frac{log(2)}{log(2)}

log(2)

log(2)

*2*\frac{log( \sqrt{3}) }{log( \sqrt{3}) }

log(

3

)

log(

3

)

= 2*log(x)

3 = log(x)

x = anti log(3)

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