Question

log8+log25+2log3−log18​

Answer 1

Answer:

To solve this problem, first you have to used log formula.

Given:

log 8+ log 25+2 log 3- log 18

Solutions:

Used log rules.

\Large\boxed{\textnormal{LOG RULES FORMULA}}

\displaystyle \log _c\left(a\right)+\log _c\left(b\right)=\log _c\left(ab\right)

\displaystyle\log _{10}\left(8\right)+\log _{10}\left(25\right)=\log _{10}\left(8\cdot \:25\right)

\displaystyle \log _{10}\left(8\cdot \:25\right)+2\log _{10}\left(3\right)-\log _{10}\left(18\right)

Multiply the numbers from left to right.

\displaystyle 8*25=200

\displaystyle \log _{10}\left(200\right)+2\log _{10}\left(3\right)-\log _{10}\left(18\right)

Answer 2

hi friend

$log(8 ) = 0.903 \\ log(25) = 1.397 \\ 2 log(3) = 0.954 \\ log(18) = 1.255 \\ now \\ 0.903 + 1.397 + 0.954 - 1.255 \\ = 3.254 - 1.225 \\ = 1.999$