Question

log81 to the base 2/ log9 to the base2​

Answer 1

Answer:

answer for the given problem is given

Answer 2

HERE IS UR ANSWER DEAR,

$= \frac{ log_{2}(81) }{ log_{2}(9) }$

$= \frac{ log_{2}( {9}^{2} ) }{ log_{2}(9) }$

$= \frac{2 log_{2}(9) }{ log_{2}(9) }$

$= 2$

❤️thanks TENNETIRAJ

U r answers are so helpful