logarithms class 11th
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Given :
To Find : Value of expression
log x
log y
log z
1
Solution:
Let say given expression is = A
= A
taking log both sides
and using
log mn = logm + logn
and log aⁿ = n loga
=> log (y/z) log x + log (z /x) log y + log ( x/y) log z = log A
using log (m/n) = log m - log n
=>( log y - log z) logx + (logz - log x) log y + (log x - log y) logz = log A
=> 0 = log A
=> A = 1
Hence expression = 1
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