logarithms question.
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Answer:
log(x)a.
Step-by-step explanation:
We know the base changing formula, using the same this can be done.
For the proof of base changing formula :
Let d = ec
⇒ b^d = b^( ec )
⇒ b^( ec ) = x { let b^d = x }
⇒ ( b^e )^c = x
⇒ a^c = x { let b^e = a }
⇒ log(a) x = c
Above, b^e = a
log(b) a = e
Also,
b^d = x
log(b) x = d
At the starting we said, d = ec,
⇒ log(b) x = log(b) a . log(a) x
⇒ { log(b) x } / { log(b) a } = log(a) x
Hence we have now proved the base changing formula, now,
⇒ log(y)a x log(x)y
Changing the base of log(y)a:
⇒ { log(x)a / log(x)y } × log(x)y
⇒ log(x)a
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