Question

logax differentiation by first principle​

Answer 1

Answer:

• Show from first principles that if f(x) = loga x then f′(x) = 1 xln a . To differentiate y = ex we will rewrite this expression in its alternative form using logarithms: ln y = x Then differentiating both sides with respect to x, ... Recall that d dx (ln y) = d dy (ln y) × dy dx .

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Answer 2

Step-by-step explanation:

Show from first principles that if f(x) = loga x then f′(x) = 1 xln a . To differentiate y = ex we will rewrite this expression in its alternative form using logarithms: ln y = x Then differentiating both sides with respect to x, ... Recall that d dx (ln y) = d dy (ln y) × dy dx .

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