logb base a=c then log b base 1/a
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Answer:
this is equal '-c'
Step-by-step explanation:
log b base a=c
log b / log a = c ..... (1)
log (1/a) = log (a^-1) = -log a
log b base (1/a) =log b / log (1/a)
= - log b / log a using eq (1)
= -c
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