Math, asked by shreyash8182, 15 days ago

= logc a-b C-a loga logb b-C (A) O (C) a + b + c then value of (ab+c.be+b.ca+b) is (B) 1 (D) logba.logcb.logac

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Answered by BrutalMaster

26

Answer:

= logc a-b C-a loga logb b-C (A) O (C) a + b + c then value of (ab+c.be+b.ca+b) is (B) 1 (D) logba.logcb.logac

Answered by Radhaisback2434

1

Step-by-step explanation:

(D) logba.logcb.logac is the answer..

Hope its help...

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