Question

= logc a-b C-a loga logb b-C (A) O (C) a + b + c then value of (ab+c.be+b.ca+b) is (B) 1 (D) logba.logcb.logac​

Answer 1

Answer:

= logc a-b C-a loga logb b-C (A) O (C) a + b + c then value of (ab+c.be+b.ca+b) is (B) 1 (D) logba.logcb.logac

Answer 2

Step-by-step explanation:

(D) logba.logcb.logac is the answer..

Hope its help...