logm^n base a =
a) m log n base a
b) n log m base a
c) logmn base a
d) log(m/n) base a
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loga (MN) = x + y = loga M + loga N [putting the values of x and y] ... (ii) From the log change of base rule formula we get, logb M = loga
jawaharreddy:
sorry
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