Question

logm/n+logn/m=log(m+n)​

Answer 1

Answer:

if logm+logn=log(m+n), find m in terms of n

We can write this as: log(mn)=log(m+n)

∴mn=m+n

Subtracting n from both the sides we get,

mn–n=m

n(m−1)=m

m−1

m

=n