Question

(logsinx)^2differentiate them

Answer 1

By applying chain rule, 
y = (logsinx)^2
dy/dx = 2log(sinx) x d/dx(logsinx)
dy/dx = 2log(sinx) x 1/sinx x d/dx(sinx)
dy/dx = 2log(sinx) x 1/sinx x cosx x 1
dy/dx = 2log(sinx).cotx

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