Question

logx(1/343)=3,then the value of x​

Answer 1

Step-by-step explanation:

hope it may help u......666....

Answer 2

Answer:

The answer to the given question is the value of this 7.

Step-by-step explanation:

Given :

$log_{x}( \frac{1}{343 } ) = 3$

To find :

we have to find the value of x.

Solution :

The given value in the question is

$log_{x}( \frac{1}{343 } ) = 3$

here in this expression, we have to find the value of x.

The value of x will be found by finding the root value of the number 1/343.

$log_{x}( \frac{ {1}^{3} }{ {7}^{3} } ) = 3$

The number 343 can be written as a cube root form as

${7}^{3}$

The number 1 can be written in a fine root form as

${1}^{3}$

$log_{x}( {1}^{3} ) - log_{x} {7}^{3} = 3$

This can be written in the form of, the power will be get multiplied by the whole value of the log

$3 log_{x}(1) - 3 log_{x}(7) = 3 \\ 3( log_{x}(1) - log_{x}(7) ) = 3$

The 3 multiplying on the right side will move on to the left side as a divisor

$log_{x}{(\dfrac{1}{7})} =\dfrac{3}{3} =1 \\ </p><p>$

$\log_{x}{(\dfrac{1}{7})} =1$

Therefore, the value of x will be 7.

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