logx^2/log8 - log2x/log 2 =-2
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1
Given,
log
2
(log
8
x)=log
8
(log
2
x)
or, log
2
(log
2
3
x)=log
2
3
(log
2
x)
or, log
2
3
1
(log
2
x)=
3
1
log
2
(log
2
x)
or, log
2
3
1
(log
2
x)=log
2
(log
2
x)
3
1
or,
3
1
log
2
x=(log
2
x)
3
1
or,
3
3
1
(log
2
x)
3
=(log
2
x)
or, (log
2
x)
2
=27
or, log
2
x=
27
=3
3
.
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