Question

(logx)^2-(logy)^2=log x/y . log xy

Answer 1

(logx+logy)(logx-logy)
log(x/y)log xy
[in  log  logm+logn=log(mn)
logm-logn=log(m/n)]

Answer 2

(logx)^2-(logy)^2=log x/y . log xy

2 log x - 2 log y = log x -log y+log x +log y

2log x -2log y = 2 log x

2log y = 1

log y = 1/2

y = e½.

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