Logx^2- logy^2=log xy log x/y
Prove this...
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Answered by
1
Answer:
Using simple log property
It will solve
Step-by-step explanation:
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Answered by
1
Answer:
RHS = (log x + log y)( log x - log y)
= (log x)^2 - (log y)^2
= LHS
hence proved
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