Math, asked by skharshitha4003, 5 hours ago

Logx^2- logy^2=log xy log x/y
Prove this...

Answers

Answered by gurukularunyadav

1

Answer:

Using simple log property

It will solve

Step-by-step explanation:

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Answered by sarikabhatnagar12

1

Answer:

RHS = (log x + log y)( log x - log y)

= (log x)^2 - (log y)^2

= LHS

hence proved

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