Question

Logx^2-logy^2=logxy logx/y
Prove this

Answer 1

Answer:

log(mn)=logm + logn and log(m/n)=logm–logn

=>(log x)²+ (log y)² –{ (log x)² –(log y)²}

=>(log x)²+ (log y)² –(log x)²+ (log y)².

= 2.(log y)² Proved