Math, asked by guntalohith, 1 year ago

logx=2log3+log25-log5 then find x.

Answers

Answered by brunila
3
take RHS
2log3+log25-log5
log3^2+log25-log5
log9+log25-log5
log225-log5
log(225/5)
log45
LHS=logx
logx=log45
x=45
formulae used:
mloga=loga^m
loga+logb=log(ab)
loga-logb=log(a/b)

rhhhhhhhh: i was near
Answered by HappiestWriter012
2
logx = 2log3+log25-log5

logx = log3^2+log25-log5

logx = log ( 9*25/5)

log x = log ( 9*5)

logx = log45

x =45.

Similar questions