logx=2log3+log25-log5 then find x.
Answers
Answered by
3
take RHS
2log3+log25-log5
log3^2+log25-log5
log9+log25-log5
log225-log5
log(225/5)
log45
LHS=logx
logx=log45
x=45
formulae used:
mloga=loga^m
loga+logb=log(ab)
loga-logb=log(a/b)
2log3+log25-log5
log3^2+log25-log5
log9+log25-log5
log225-log5
log(225/5)
log45
LHS=logx
logx=log45
x=45
formulae used:
mloga=loga^m
loga+logb=log(ab)
loga-logb=log(a/b)
rhhhhhhhh:
i was near
Answered by
2
logx = 2log3+log25-log5
logx = log3^2+log25-log5
logx = log ( 9*25/5)
log x = log ( 9*5)
logx = log45
x =45.
logx = log3^2+log25-log5
logx = log ( 9*25/5)
log x = log ( 9*5)
logx = log45
x =45.
Similar questions
Political Science,
10 months ago
Social Sciences,
10 months ago
English,
1 year ago
Chemistry,
1 year ago
Environmental Sciences,
1 year ago
English,
1 year ago
Math,
1 year ago