Question

logx(9/16)=-2 then find x

Answer 1

Answer:

$log(x) = - \frac{32}{9} \\ \\ x = {e}^{ - \frac{32}{9} }$

Answer 2

The value of x is $\frac{4}{3}$.

Step-by-step explanation:

Given : Expression $\log_x (\frac{9}{16})=-2$

To find : The value of x ?

Solution :

Using logarithmic property,

$\log_a b=c\Rightarrow a^c=b$

Here, a=x, $b=\frac{9}{16}$ and c=-2

So, $x^{-2}=\frac{9}{16}$

$\frac{1}{x^{2}}=\frac{3^2}{4^2}$

$x^2=(\frac{4}{3})^2$

$x=\frac{4}{3}$

Therefore, the value of x is $\frac{4}{3}$.

#Learn more

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