Question

logx base 5 + logx base25 + logx base 625 =7/4 then x=​

Answer 1

Answer:

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Step-by-step explanation:

log x base 5 + log x base 5² + log x base 5⁴ = 7/4

(log x base 5) + 1/2 × log x base 5² + 1/4 × log x base 5 = 7/4

(4log x base 5+ 2 log x base 5 + log x base 5)/4 = 7/4

7log x base 5 = 7

log x base 5 = 1

x = 5

Answer 2

Step-by-step explanation:

WE ARE GIVEN,

$log_{5}x + log_{25}x + log_{625}x = \frac{7}{4 } \\ = = > log_{5}x + \frac{1}{2} log_{5}x + \frac{1}{4} log_{5}x= \frac{7}{4 } \\ = = > log_{5}x (1 + \frac{1}{2} + \frac{1}{4} ) = \frac{7}{4} \\ = = > log_{5}x \times \frac{7}{4} = \frac{7}{4} \\ = = > log_{5}x = 1 \\ = = > x = 5$

X=5