Question

logx base k × log k base 5 =log 5 base x , k not equal to 1 ,k greater than 0​

Answer 1

Answer:

Using Logarithmic Property

logba=log(a)log(b)logb⁡a=log(a)log(b)

Your equation becomes

log(x)log(k)×log(k)log(5)=log(5)log(k)log(x)log(k)×log(k)log(5)=log(5)log(k)

Which on further solving becomes

log(x)=log(5)×log(5)log(k)=(log(5))2log(k)log(x)=log(5)×log(5)log(k)=(log(5))2log(k)

and finally the Value of x becomes

x=e(log(5))2log(k)