logx+log(x-1) = 1 solution
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hey mate
logx+log(x-1) =1
log{X(x-1)} =1
log(x²-x) =1
log(x²-x) =log10
log cancel each
x²-x=10
x²-x-10=0
and solve this equation
logx+log(x-1) =1
log{X(x-1)} =1
log(x²-x) =1
log(x²-x) =log10
log cancel each
x²-x=10
x²-x-10=0
and solve this equation
payal6071:
value2 h answer sheet m x ki
bhai kha gye
solve nhi hua Kya bro
Nhi Ho rha h aapne jo phle jo solution btaya vo mere hi aagya tha lekin aage solve nhi ho rha h
OK bro
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