logx+log(x-5)=log6 ?
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Logx+log(x-5) = log6
We know that =>
logM+logN= log(M.N)
log{x.(x-5)} = log6
log is cancelled
x²-5x= 6
x²-5x-6= 0
x²-6x+x-6 = 0
x(x-6)+1(x-6) = 0
(x+1)(x-6) = 0
______
x= -1,6
_______
________ Ans
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