Math, asked by AryanNair103, 10 months ago

logx + [ log ( x/y^8 )/ (log x)^2 + (log y) ^2 ] = 2.

logy + [ log ( x^8/y )/ (log x)^2 + (log y) ^2 ] = 0

find value of xy​

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Answers

Answered by shashiranjanpandey19
1

Answer:

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