Question

logx + [ log ( xy^8 )/ (log x)^2 + (log y) ^2 ] = 2. logy + [ log ( x^8/y )/ (log x)^2 + (log y) ^2 ] = 0 find value of x and y​

Answer 1

Answer:

logx + [ log ( xy^8 )/ (log x)^2 + (log y) ^2 ] = 2. logy + [ log ( x^8/y )/ (log x)^2 + (log y) ^2 ] = 0 find value of x and y

Step-by-step explanation:

thank you for asking me question