Math, asked by anitakumawat91851, 9 months ago

logX =log3+2log2-3/4log16​

Answers

Answered by Anonymous
1

 log(x)  =  log(3)  +  log(2)  -  \frac{3}{4}  log(16)  \\  log(x)  =  log(3 \times 2)  -  \frac{3}{4}  \times 4log(2)  \\  log(x)  =  log(6)  - 3 log(2)  \\  log(x)  =  \frac{ log(6) }{3 log(2) }  \\ x = 1

Answered by chinki004
0

Answer:

answer is x==>1................

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