Question

logx\log5=log36\log6=log64\logy find x+y

Answer 1

logX/log5 = log6²/log6
=> logX/log5= 2log6/log6
(We know that log(a^b) = blog(a))
=> logX/log5 = 2log6/log6
LogX/log5=2
=> logX=2log5=log5²=log25
Taking antilog, X=25
Now, Log64/logY = 2log6/log6 = 2
=> 2log8/logY =2
=> log8/logY = 1
=> logY = log8
=> Y = 8

Now, X + Y = 25 + 8 = 33

Answer 2

Answer:

I hope you will understand