Math, asked by AkhilaMaryson, 6 months ago

logx to the base e is greater than log X to the base 10,why?​

Answers

Answered by dhanvantijagwani99
0

Answer:

can u write a proper question please so I can answer this question.

Step-by-step explanation:

hope it helps you

Answered by REDPLANET
0

Answer:

Follow for 50 point que.

log_ex = \frac{logx}{loge}   is greater than log_{10}x = \frac{logx}{log10}

because log e = 0.434294482 , log 10 = 1

So larger the denominator smaller the value

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