logx/y+logy/z+logz/x=0
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Answered by
7
Step-by-step explanation:
To prove logx/y + logy/z + logz/x = 0
From given :- logx/y+logy/z+logz/x
Using the property of "log"
loga+logb+logc = log (abc)
- ∴ log(x/y× y/z×z/x)
- = log(x/z×z/x)
- = log(1)
We know that log(1) = 0
since , Proved log(x/y+y/z+z/x) = 0
Answered by
3
Step-by-step explanation:
here positive log x and negative logx is cancelled
similarly same to logy and logz
here logx/y =logx -logy
it's an identity
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