Question

logx/y+logy/z+logz/x=0​

Answer 1

Step-by-step explanation:

To prove logx/y + logy/z + logz/x = 0

From given :- logx/y+logy/z+logz/x

Using the property of "log"

loga+logb+logc = log (abc)

• ∴ log(x/y× y/z×z/x)

• = log(x/z×z/x)

• = log(1)

We know that log(1) = 0

since , Proved log(x/y+y/z+z/x) = 0

Answer 2

Step-by-step explanation:

$given \: \\ log \frac{x}{y} + log \frac{y}{z} + log \frac{z}{x} \\ = logx - logy + logy - logz \\ + logz - logx \\ = 0$

here positive log x and negative logx is cancelled

similarly same to logy and logz

here logx/y =logx -logy

it's an identity