logx1/25 = -1/2 find x
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Answered by
3
Answer:
1/5
Step-by-step explanation:
Hello Shyaamal Tripathi, x = 1/5
Solution: logx 25 + logx 1/125 - logx 5 = 2
So logx ( 25 x 1/125 x 1/5) = 2
==> logx 1/25 = 2
==> x 2 = 1/25 = 1/52
So x = 1/5
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Answered by
0
Answer:
Let logx to the base 5=a, 5^a=x,alog5=logx
logx to the base 7=b, 7^b=x,blog7=logx
logx to the base 25=c,25^c=x,5^2c=x clog5^2=logx. So a=logx/log5, b=logx/log7 & c=logx/2log5. a+b=logx/log5+logx/log7=logx(1/log5+1/log7)/. As per question a+b=2c, so logx(log10-log5+log10-log7)=logx(2-log35)=logx/2log5, or, logx(2-log35-log25)=0
Or, log x(2-log35/25)=0=log1
Or,logx=log1, or, x=1
Step-by-step explanation:
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