Question

Logx3*logx/3 3+logx/81 3=0

Answer 1

Answer:

pls mark it as brainlest answer

Answer 2

Answer:

value of x is 9

Step-by-step explanation:

$log_{3} x*(log_{3 } (x/3) +log_{3} (x/81)\\\\=log_{3} x(log_{3} x-log_{3} 3)+log_{3} x+log_{3} 81\\\\=(log_{3} x)^{2} -log_{3} x+log_{3} x-log_{3} 81\\\\=2log_{3} x-log_{3} 81=0\\\\=2log_{3} x=log_{3} 81\\\\=log_{3} x=\frac{1}{2} log_{3} 81\\\\ \\ =\frac{1}{2} log_{3} 3^{4} \\ (log_{a} a=1)\\ =2\\\\log_{3} x=2\\\\x=3^{2} =9$

value of x is 9

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