Math, asked by dhyaneswar2008, 4 hours ago

logxa.logyb=logxb.logya

Answers

Answered by udaisingh7177

0

Answer:

L.H.S. :

logxa . logyb = logx/ loga . logy/logb

...

R.H.S. :

logxb . logya = logx / logb . loga/logy

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