Question

logxb-logxa=logxc-logxb then ac=​

Answer 1

Step-by-step explanation:

$\sf {log}_{x}{b} - {log}_{x}{a} = {log}_{x}{b} -{log}_{x}{b} \\ \\ \sf \longrightarrow {log}_{x}{b} + {log}_{x}{b} = {log}_{x}{a} + {log}_{x}{c} \\ \\ \sf \longrightarrow {log}_{x}{{b}^{2}} = {log}_{x}{ac} \\ \\ \sf \longrightarrow {b}^{2} = ac$

❣️NIRANJAN45❣️

Answer 2

Answer:

b² = ac

Step-by-step explanation:

Some properties of logarithm.

log a + log b = log ab

log a - log b =  log $\frac{a}{b}$

~~~~~~

log(xb) - log(xa) = log(xc) - log(xb)

log $\frac{xb}{xa}$ = log $\frac{xc}{xb}$ ⇒ $\frac{b}{a}$ = $\frac{c}{b}$ ⇒ b² = ac