Physics, asked by ayushkumar7221656, 11 hours ago

lon. 8 (Mark. 1) A space craft travelling in space at a speed of 120km/s fires retro engines for 5 seconds to attain a speed of 80 km/s. iii. The distance travelled in 12 seconds from the starting of retro engines is Select from the Answers below​

Answers

Answered by HAWKEYE04
0

Answer:

1160km

Explanation:

For 1st 5 sec it moves with 120 km/s. So distance travelled in this duration is

d= v×t = 120×5= 600km/s

and after 5 sec its retro engine travelled with 80km/s for 12-5 sec= 7 sec

so distance travelled= v×t = 560km/s

Total distance travelled=(600+560) = 1160km

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