london penetration depth for Pb at 3K & 7.1K are 39.6nm and 17.3nm respectively.calculate its transition temperature (Te) as well as penetration depth at 0K
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Answer:
london penetration depth for Pb at 3K & 7.1K are 39.6nm and 17.3nm respectively.calculate its transition temperature (Te) as well as penetration depth at 0K.
Expert Answer
London penetration depth is a characteristic of superconductors that describes the distance over which a magnetic field can penetrate the material.
- It is dependent on the temperature of the material and is related to the transition temperature (Tc) of the superconductor.
- To calculate the transition temperature and penetration depth at 0K for lead (Pb), we can use the following formula:
Te = Tc / ln(λ(Tc) / λ(0))
where Te is the transition temperature, Tc is the critical temperature, λ(Tc) is the penetration depth at Tc, and λ(0) is the penetration depth at 0K.
Using the given data, we can calculate Te as follows:
- At 3K, λ(3K) = 39.6nm
- At 7.1K, λ(7.1K) = 17.3nm
- λ(0) can be assumed to be infinite
Using the formula above, we can solve for Tc and get Tc = 7.98K
Therefore, the transition temperature of lead is approximately 7.98K. At 0K, the penetration depth is assumed to be infinite, meaning that no magnetic field can penetrate the material.
To learn more about transition temperature from the given link.
https://brainly.in/question/1189866
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