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2.6 If a = 1, b = -2 and c = 3 then find the value of a + b2 + c2 + ab + bc + ca.
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GivEn:
- a = 1
- b = (-2)
- c = 3
To finD:
- value of a+b²+c²+ab+bc+ca
Solution:
In this given question, we have given value of a,b and c respectively.
To find the value of a+b²+c²+ab+bc+ca, We have to put the values of a,b and c in it.
Putting values:
a + b²+ c² +ab+bc+ca
→ 1 + (-2)² + 3² + 1×(-2) + (-2)×3 + 3×1
→ 1 + 4 + 9 + (-2) +(-6) +3
→ 1 + 4 + 9 - 2 - 6 +3
→ (1+4+9+3) -(2+6)
→ 17 - 8
→ 9
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Therefore,
value of a+b²+c² + ab + bc + ca in the given value of a,b and c is 9
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