long answer type:
f a=1, b = 2,C=3 find the value of
(a3 + b3 + c3 -3abc)
ab+bc+ca-(A2+b2+c2
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Δ = a1 & b1 & c1 a2 & b2 & c2 a3 & b3 & c3 Δ = a1(b2c3 - b3c2) + b1(a3c2 - a2c3) + c1(a2b3 - a3b2) We have to find B2 & C2 B3 & C3 Here, B2 is cofactor
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