Long answer type question
1 By how much is a sum of a^4 -6a^2b^2+b^4 and -2a^4+5a^2 b^2+3b^4 greater than -a^4-a^2 b^2-4b^4 ?
Answers
Answered by
6
Given : sum of a^4 -6a^2b^2+b^4 and -2a^4+5a^2 b^2+3b^4
To Find : How much it is greater than -a^4-a^2 b^2-4b^4 ?
Solution:
sum of a⁴ -6a²b²+b⁴ and -2a⁴+5a² b²+3b⁴
= a⁴ -6a²b²+b⁴ + ( -2a⁴+5a² b²+3b⁴)
= a⁴ -6a²b²+b⁴ -2a⁴+5a² b²+3b⁴
= -a⁴ -a²b² + 4b⁴
greater than -a⁴-a² b²-4b⁴
= -a⁴ -a²b² + 4b⁴ - (-a⁴-a² b²-4b⁴)
= -a⁴ -a²b² + 4b⁴ + a⁴+a²b² + 4b⁴
= 8b⁴
sum of a⁴ -6a²b²+b⁴ and -2a⁴+5a² b²+3b⁴ is greater than -a⁴-a² b²-4b⁴ by 8b⁴
Learn More:
3p³q+2p²q+7 ; 2p²q+4pq-2p³q Add the given polynomial.
https://brainly.in/question/11760332
Answered by
3
Answer :
8b⁴
Solution in attachment
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