Math, asked by pallavigarg8630, 3 months ago

Long Answer Type Questions
Bribio
15. In the given figure, AB = 8 cm, BC = 3 cm and BE is parallel to CD.
(4 marks
E
ABEN A
AB BE
CD
3
ACE
>
С
AC
(i) Find
BE
Area of AABE
(a)
(b)
CD
Area of quadrilateral BCDE
(ii) What is the special name given to the quadrilateral BCDE?
16. In the given figure, D, E and F are the points on sides BC, CA and AB, respo​

Answers

Answered by MizzCornetto
39

{❥}\fbox\red{A}\fbox\orange{N}\fbox\purple{S}\fbox\green{W}\fbox\blue{E}\fbox\pink{R}

Required answer-:

Perimeter of the quadrilateral =10+8+5+13=36cm

Area of the quadrilateral=area of the triangle ABD+area of the triangle DBC.

Area of the triangle DBC=\frac{1}{2}×B×H

=\frac{1}{2}×5×12

=30cm²

Area of the Triangle ABD=\sqrt{s(s−a)(s−b)(s−c)}

Here, s=\frac{10+12+8}{2}

=15cm

Therefore area=\sqrt{15(15−10)(15−12)(15−8)}

=15\sqrt{7cm²}

Therefore area of the quadrilateral=15+15\sqrt{7}=15(1+\sqrt{7})cm²

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