Question

Long division of hcf 128,136,512

Answer 1

Here's your answer:

we first divide the smallest and the second smallest HCF and once the remainder comes we multiply it with the divisor for example in this question the divisor was 128 so we take 128 and divide it with the remainder (8). we follow this process till we get the remainder as 0.

the HCF is the second last remainder. in this problem we can say that 8 is the HCF. Now we divide our third number with the HCF. when we get zero as the remainder then the divisor is known as the HCF.(8)