Question

long vertical tube contains all to a height of 42.5 CM in the density of the oil is 0.8 CM calculate the maximum lateral pressure exerted by the all on the sides of the cube a bigger has 2.5 CM of Mulberry in IT calculate the pressure exerted by the Mercury on the bottom of the beaker take density of Mercury as 13.6 grams and ji = 10 M per second -2

Answer 1

Since it is in equilibrium, the pressure exerted by the column of oil has to equal the pressure exerted by the unknown liquid. Since pressure is calculated by rho*g*h, we can set the equations equal to each other:

rho(oil)*g*h(oil) = rho(x)*g*h(x)

It's easy to see that g cancels out. Solving for rho(x) you get:

rho(x) = rho(oil)*h(oil)/h(x)

We don't directly know h(x) but we do know the difference in column height is 3 cm and we know the oil height so h(x) = h(oil)-3cm

The equation now is:

rho(x) = rho(oil)*h(oil)/[h(oil)-3cm]

Replace with known quantities and solve