Question

long
Wheels is divided by tx - 2) leaves remainder 2. und
nerede-2 Find a and​

Answer 1

Answer:

The number divided by 9 gives remainder 2.

So, the number is 9m+2 for some non-negative integer m .

Now, m may give remainder r when divided by 5 .

So, m=5n+r for some non-negative n and r=0,1,2,3 or 4.

Putting value of m in expression for original value, it becomes

9(5n+r)+2=45n+9r+2 for some non-negative integer and r=0,1,2,3 or 4.

So, it is a multiple of 45+(2,11,20,29 or 38 ).

So, possible remainders when divided by 45 are 2,11,20,29 or 38 .

Ans.: 2,11,20,29 or 38 .

Step-by-step explanation:

Answer 2

Answer:

A number leaves a remainder 2 when divided by 9. What could be the remainder when it is divided by 45?

Why do toppers choose BYJU'S for JEE preparation?

The number divided by 9 gives remainder 2.

So, the number is [math]9m+2[/math] for some non-negative integer [math]m[/math].

Now, [math]m[/math] may give remainder [math]r[/math] when divided by [math]5[/math].

So, [math]m=5n+r[/math] for some non-negative [math]n[/math] and [math]r=0, 1, 2, 3[/math] or [math]4.[/math]

Putting value of [math]m[/math] in expression for original value, it becomes

[math]9(5n+r)+2=45n+9r+2[/math] for some non-negative integer and [math]r=0, 1, 2, 3[/math] or [math]4.[/math]

So, it is a multiple of [math]45+(2, 11, 20, 29[/math] or [math]38[/math]).

So, possible remainders when divided by [math]45[/math] are [math]2, 11, 20, 29[/math] or [math]38[/math].

Ans.: [math]2, 11, 20, 29[/math] or [math]38[/math].