Longest rod that can be placed in a room 15*12*9
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Hi ,
Dimensions of the room,
Length = l = 15 units
Breadth = b = 12 units
Height = h = 9 units
Length of the longest rod placed in
the room = diagonal of the room
= √( l² + b² + h² )
= √ ( 15² + 12² + 9² )
= √ ( 225 + 144 + 81 )
= √ 450
= √ ( 3 × 3 × 5 × 5 ×2 )
= 15√2 units
I hope this helps you.
:)
Dimensions of the room,
Length = l = 15 units
Breadth = b = 12 units
Height = h = 9 units
Length of the longest rod placed in
the room = diagonal of the room
= √( l² + b² + h² )
= √ ( 15² + 12² + 9² )
= √ ( 225 + 144 + 81 )
= √ 450
= √ ( 3 × 3 × 5 × 5 ×2 )
= 15√2 units
I hope this helps you.
:)
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