Question

longitudinal waves travel at the speed of 10m/s in a coiled spring. if the distance between two successive rarefraction is 1.0cm. find the frequency of the wave?

Answer 1

The frequency of the wave will be 1000 Hz.

Explanation :

The distance between two successive rarefraction is nothing but the wavelength of the wave.

Hence

λ = 1 cm = 0.01 m

Given speed of the wave = 10 m/s

we know that frequency of the wave is the ratio of speed to wavelength

hence

frequency = speed/wavelength

= v/λ

= 10/0.01

= 1000 Hz

Hence the frequency of the wave will be 1000 Hz.

Answer 2

Answer:

here is ur answer

Explanation:

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