Question

- Longth of the shadow of a 15 meter high pole is 1553 metro at 9.00 Am. Then what is the angle of elevakton of the Sunrays with the ground at the time?​

Answer 1

Step-by-step explanation:

Length of pole is XY=15 m

Shadow of pole is =YZ=5

3

angle of elevation of sun with ground is ϕ as shown in figure.

Here in a right angled triangle,

tan(90

∘

−ϕ)=

XY

YZ

=

15

5

3

=

3

1

⇒tan(90

∘

−ϕ)=

3

1

⇒90

∘

−ϕ=60

∘

⇒ϕ=30

∘

Elevation is 30

∘