Look at the given figure and prove the following:
a)∆ABD is congurent to ∆CBD
b) angle A= angle C
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Step-by-step explanation:
a) In ΔABD and ΔCBD
AD is parallel to BC and BD is transversal
Angle ADB= Angle CBD (A. I. A)
Angle ABD= Angle CDB (A. I. A)
BD = DB (Common)
So, ΔABD is congruent to ΔCBD (by A.S.A)
Angle A = Angle C (by C. P. C. T)
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