Question

look at the image and answer​

Answer 1

Answer:

1.total resistance=20+4(in series)

=24ohm

2.V=IR(ohms law)

6=I×24

I=0.4ampere

3.V(of lamp)=0.4(20)

V=8volts

Power of lamp (P)=VI

=8×0.4=3.2watt

4.V(of conductor)=IR=0.4×4=1.6volts