Question

Look at the pic and please answer above question​

Answer 1

Answer:

here's your answer and hopefully it helps

bye bye

Answer 2

Answer:

i)27b^3/64a^12

ii)16y^6/x²

Step-by-step explanation:

i) (256a^16/81b^4)^-3/4

= (81b^4/256a^16)^3/4

= (3b/4a^4)^3 [(81b^4)^1/4 = 3b and (256a^16)^1/4 = 4a^4)]

= 27b^3/64a^12

ii) (64x^-3*y^9)^2/3 = (4³x^-3*y^9)^2/3

=(4³/x^3*y^9)^2/3

=(4y³/x)^(3*2/3)

= (4y³/x)^2

= 16y^6/x²