look at the picture
need anwer (ii)ASAP....
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Answer:
given
tanA = 1/√3 = tan30°
so, angle A = 30°
in ∆ ABC
A+B+C= 180°
B+C= 180° - A
B+C = 180° - 30°
B+C = 150°
now
cosAcosC - sinAsinC
= cos(A+C)
= cos 150°
= cos(180-30)
= -cos30° ( cos(180-A) = -cosA)
= -√3/2
Answered by
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Answer:
ans is 0
Step-by-step explanation:
cos a cos c - sin a sin c
cos a = adjacent/hypotenuse = root 3/2
cos c= 1/2
sin a = opposite/hypotenuse =root3/2
sin c=1/2
cos a cos c - sin a sin c
root3/2 x 1/2 - root3/2 x 1/2
=0
hope this answer was helpful
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